本文详解 TypeScript 中为对象动态添加属性的常见报错及解决方案。通过定义包含索引签名 [idx: string]: any 的接口，可实现动态属性赋值。同时介绍将对象作为参数传递及方法返回对象时的类型处理，确保代码类型安全且无编译错误。
1. 定义
TypeScript 对象由键值对构成，值可为标量、函数、数组或对象等，例如：
var object_name = {
key1: "value1", // 标量
key2: "value",
key3: function() {
// 函数
},
key4:["content1", "content2"] //集合
}
//访问对象
object_name.key1 // value1
object_name.key4 // ["content1", "content2"]
2. TypeScript 类型模板
var sites = {
site1: "",
site2: 0,
sayHello: function () { } // 类型模板
};
sites.site1 = "site1"
sites.site2 = 2
sites.sayHello = function () {
console.log("hello " + sites.site1 + sites.site2);
};
sites.sayHello(); // hello site1 2
3. 为对象动态添加属性
若使用上述方法定义对象，则无法实现动态添加属性
let people = {
name: "hwm",
age: 18,
sayHello: ()=> {}
}
people.sex = "man"
上述代码将引发错误：
3.1 解决方法
定义含数组属性的接口，并使对象实现该接口
interface obj {
[idx: string]: any
}
let people: obj = {}
people.name = "hwm"
people.age = 18
console.log(people) // { name: 'hwm', age: 18 }3.2 对象作为参数传递
方法一：
private ParamObj(objT: {name: string, age: number}) {
let people = objT
console.log(objT)
}
let people = {name: "hwm", age: 18}
this.ParamObj(people) // {name: "hwm", age: 18}
方法二：
interface obj {
[idx: string]: any
}
private ParamObj(objT: obj) {
let people = objT
console.log(objT)
}
let people:obj = {}
people.name = "lll"
people.age = 20
this.ParamObj(people) // {name: "lll", age: 20}
3.3 方法返回对象
private ReturnObj(): {name: string, age: number}{
let people = {name: "hwm", age: 18}
return people
}
let res = this.ReturnObj()
console.log(res) // {name: "hwm", age: 18}
3.4 对象数组
let tbl: {<!--{C}%3C!%2D%2D%20%2D%2D%3E-->name: string, age: number}[] = []总结
至此关于 TypeScript 动态添加对象属性的介绍结束，更多相关 TS 动态属性内容请查阅本站往期文章或继续浏览下文，感谢支持！